1/1000th: The Sports Photography of Bob Martin

1/1000th: The Sports Photography of Bob Martin

Matematika Sekolah Dasar tolong bantu saya mengerjakan tugas ini ya ​

tolong bantu saya mengerjakan tugas ini ya ​

Jawaban:

  • A + B = 37/20 atau 1 17/20
  • A - B = 1/20
  • A × B = 171/200
  • B ÷ A = 18/19

Langkah-langkah:

Mencari nilai A

[tex] \sf \frac{3}{4} + \frac{1}{5} [/tex]

[tex] \sf = \frac{(3 \times 5)}{(4 \times 5)} + \frac{(1 \times 4)}{(5 \times 4)} [/tex]

[tex] \sf = \frac{15}{20} + \frac{4}{20} [/tex]

[tex] \sf = \frac{19}{20} [/tex]

Mencari nilai B

[tex] \sf \frac{1}{2} + \frac{2}{5} [/tex]

[tex] \sf = \frac{(1 \times 5)}{(2 \times 5)} + \frac{(2 \times 2)}{(5 \times 2)} [/tex]

[tex] \sf = \frac{5}{10} + \frac{4}{10} [/tex]

[tex] \sf = \frac{9}{10} [/tex]

a.) Mencari nilai A + B

[tex] \sf A + B[/tex]

[tex] \sf = \frac{19}{20} + \frac{9}{10} [/tex]

[tex] \sf = \frac{19}{20} + \frac{(9 \times 2)}{(10 \times 2)} [/tex]

[tex] \sf = \frac{19}{20} + \frac{18}{20} [/tex]

[tex] \sf = \frac{37}{20} [/tex]

[tex] \sf = 1 \frac{17}{20} [/tex]

b.) Mencari nilai A - B

[tex] \sf A - B[/tex]

[tex] \sf = \frac{19}{20} - \frac{9}{10} [/tex]

[tex] \sf = \frac{19}{20} - \frac{(9 \times 2)}{(10 \times 2)} [/tex]

[tex] \sf = \frac{19}{20} - \frac{18}{20} [/tex]

[tex] \sf = \frac{1}{20} [/tex]

c.) Mencari nilai A × B

[tex] \sf A \times B[/tex]

[tex] \sf = \frac{19}{20} \times \frac{9}{10} [/tex]

[tex] \sf = \frac{19 \times 9}{20 \times 10} [/tex]

[tex] \sf = \frac{171}{200} [/tex]

d.) Mencari nilai B ÷ A

[tex] \sf B \div A[/tex]

[tex] \sf = \frac{9}{10} \div \frac{19}{20} [/tex]

[tex] \sf = \frac{9}{10} \times \frac{20}{19} [/tex]

[tex] \sf = \frac{9}{(10 \div 10)} \times \frac{(20 \div 10)}{19} [/tex]

[tex] \sf = \frac{9}{1} \times \frac{2}{19} [/tex]

[tex] \sf = \frac{18}{19} [/tex]

Yang dapat disimpulkan:

Jadi nilai yang didapat berturut-turut adalah 1 17/20 ; 1/20 ; 171/200 ; 18/19.

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